Optimal. Leaf size=227 \[ -\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}-\frac {b d^2 (d e-c f) \log \left (c^2+2 c d x+d^2 x^2+1\right )}{2 \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2}-\frac {b d}{2 (e+f x) \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2}+\frac {b d^2 (-c f+d e+f) (d e-(c+1) f) \tan ^{-1}(c+d x)}{2 f \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2} \]
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Rubi [A] time = 0.30, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.444, Rules used = {5045, 1982, 709, 800, 634, 618, 204, 628} \[ -\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}-\frac {b d^2 (d e-c f) \log \left (c^2+2 c d x+d^2 x^2+1\right )}{2 \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2}-\frac {b d}{2 (e+f x) \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2}+\frac {b d^2 (-c f+d e+f) (d e-(c+1) f) \tan ^{-1}(c+d x)}{2 f \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 204
Rule 618
Rule 628
Rule 634
Rule 709
Rule 800
Rule 1982
Rule 5045
Rubi steps
\begin {align*} \int \frac {a+b \tan ^{-1}(c+d x)}{(e+f x)^3} \, dx &=-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {(b d) \int \frac {1}{(e+f x)^2 \left (1+(c+d x)^2\right )} \, dx}{2 f}\\ &=-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {(b d) \int \frac {1}{(e+f x)^2 \left (1+c^2+2 c d x+d^2 x^2\right )} \, dx}{2 f}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {(b d) \int \frac {d (d e-2 c f)-d^2 f x}{(e+f x) \left (1+c^2+2 c d x+d^2 x^2\right )} \, dx}{2 f \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {(b d) \int \left (\frac {2 d f^2 (d e-c f)}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}+\frac {d^2 \left (d^2 e^2-4 c d e f-\left (1-3 c^2\right ) f^2-2 d f (d e-c f) x\right )}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) \left (1+c^2+2 c d x+d^2 x^2\right )}\right ) \, dx}{2 f \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}+\frac {\left (b d^3\right ) \int \frac {d^2 e^2-4 c d e f-\left (1-3 c^2\right ) f^2-2 d f (d e-c f) x}{1+c^2+2 c d x+d^2 x^2} \, dx}{2 f \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}-\frac {\left (b d^2 (d e-c f)\right ) \int \frac {2 c d+2 d^2 x}{1+c^2+2 c d x+d^2 x^2} \, dx}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}+\frac {\left (b d \left (4 c d^2 f (d e-c f)+2 d^2 \left (d^2 e^2-4 c d e f-\left (1-3 c^2\right ) f^2\right )\right )\right ) \int \frac {1}{1+c^2+2 c d x+d^2 x^2} \, dx}{4 f \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}-\frac {b d^2 (d e-c f) \log \left (1+c^2+2 c d x+d^2 x^2\right )}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}-\frac {\left (b d \left (4 c d^2 f (d e-c f)+2 d^2 \left (d^2 e^2-4 c d e f-\left (1-3 c^2\right ) f^2\right )\right )\right ) \operatorname {Subst}\left (\int \frac {1}{-4 d^2-x^2} \, dx,x,2 c d+2 d^2 x\right )}{2 f \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}\\ &=-\frac {b d}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right ) (e+f x)}+\frac {b d^2 (d e-f-c f) (d e+f-c f) \tan ^{-1}(c+d x)}{2 f \left (d^2 e^2-2 c d e f+f^2+c^2 f^2\right )^2}-\frac {a+b \tan ^{-1}(c+d x)}{2 f (e+f x)^2}+\frac {b d^2 (d e-c f) \log (e+f x)}{\left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}-\frac {b d^2 (d e-c f) \log \left (1+c^2+2 c d x+d^2 x^2\right )}{2 \left (d^2 e^2-2 c d e f+\left (1+c^2\right ) f^2\right )^2}\\ \end {align*}
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Mathematica [C] time = 0.80, size = 175, normalized size = 0.77 \[ \frac {-\frac {a+b \tan ^{-1}(c+d x)}{(e+f x)^2}+\frac {1}{2} b d^2 \left (-\frac {2 f}{d (e+f x) \left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )}-\frac {4 f (c f-d e) \log (d (e+f x))}{\left (\left (c^2+1\right ) f^2-2 c d e f+d^2 e^2\right )^2}-\frac {i \log (-c-d x+i)}{(d e-(c-i) f)^2}+\frac {i \log (c+d x+i)}{(d e-(c+i) f)^2}\right )}{2 f} \]
Antiderivative was successfully verified.
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fricas [B] time = 2.13, size = 682, normalized size = 3.00 \[ -\frac {a d^{4} e^{4} - {\left (4 \, a c - b\right )} d^{3} e^{3} f + 2 \, {\left (3 \, a c^{2} - b c + a\right )} d^{2} e^{2} f^{2} - {\left (4 \, a c^{3} - b c^{2} + 4 \, a c - b\right )} d e f^{3} + {\left (a c^{4} + 2 \, a c^{2} + a\right )} f^{4} + {\left (b d^{3} e^{2} f^{2} - 2 \, b c d^{2} e f^{3} + {\left (b c^{2} + b\right )} d f^{4}\right )} x - {\left (2 \, b c d^{3} e^{3} f - {\left (5 \, b c^{2} + 3 \, b\right )} d^{2} e^{2} f^{2} + 4 \, {\left (b c^{3} + b c\right )} d e f^{3} - {\left (b c^{4} + 2 \, b c^{2} + b\right )} f^{4} + {\left (b d^{4} e^{2} f^{2} - 2 \, b c d^{3} e f^{3} + {\left (b c^{2} - b\right )} d^{2} f^{4}\right )} x^{2} + 2 \, {\left (b d^{4} e^{3} f - 2 \, b c d^{3} e^{2} f^{2} + {\left (b c^{2} - b\right )} d^{2} e f^{3}\right )} x\right )} \arctan \left (d x + c\right ) + {\left (b d^{3} e^{3} f - b c d^{2} e^{2} f^{2} + {\left (b d^{3} e f^{3} - b c d^{2} f^{4}\right )} x^{2} + 2 \, {\left (b d^{3} e^{2} f^{2} - b c d^{2} e f^{3}\right )} x\right )} \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right ) - 2 \, {\left (b d^{3} e^{3} f - b c d^{2} e^{2} f^{2} + {\left (b d^{3} e f^{3} - b c d^{2} f^{4}\right )} x^{2} + 2 \, {\left (b d^{3} e^{2} f^{2} - b c d^{2} e f^{3}\right )} x\right )} \log \left (f x + e\right )}{2 \, {\left (d^{4} e^{6} f - 4 \, c d^{3} e^{5} f^{2} + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{4} f^{3} - 4 \, {\left (c^{3} + c\right )} d e^{3} f^{4} + {\left (c^{4} + 2 \, c^{2} + 1\right )} e^{2} f^{5} + {\left (d^{4} e^{4} f^{3} - 4 \, c d^{3} e^{3} f^{4} + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{2} f^{5} - 4 \, {\left (c^{3} + c\right )} d e f^{6} + {\left (c^{4} + 2 \, c^{2} + 1\right )} f^{7}\right )} x^{2} + 2 \, {\left (d^{4} e^{5} f^{2} - 4 \, c d^{3} e^{4} f^{3} + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{3} f^{4} - 4 \, {\left (c^{3} + c\right )} d e^{2} f^{5} + {\left (c^{4} + 2 \, c^{2} + 1\right )} e f^{6}\right )} x\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 438, normalized size = 1.93 \[ -\frac {d^{2} a}{2 \left (d f x +d e \right )^{2} f}-\frac {d^{2} b \arctan \left (d x +c \right )}{2 \left (d f x +d e \right )^{2} f}-\frac {d^{2} b}{2 \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right ) \left (d f x +d e \right )}-\frac {d^{2} b f \ln \left (f \left (d x +c \right )-c f +d e \right ) c}{\left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}+\frac {d^{3} b \ln \left (f \left (d x +c \right )-c f +d e \right ) e}{\left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}+\frac {d^{2} b f \arctan \left (d x +c \right ) c^{2}}{2 \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}-\frac {d^{3} b \arctan \left (d x +c \right ) c e}{\left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}+\frac {d^{4} b \arctan \left (d x +c \right ) e^{2}}{2 f \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}+\frac {d^{2} b f \ln \left (1+\left (d x +c \right )^{2}\right ) c}{2 \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}-\frac {d^{3} b \ln \left (1+\left (d x +c \right )^{2}\right ) e}{2 \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}}-\frac {d^{2} b f \arctan \left (d x +c \right )}{2 \left (c^{2} f^{2}-2 c d e f +d^{2} e^{2}+f^{2}\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.43, size = 409, normalized size = 1.80 \[ -\frac {1}{2} \, {\left (d {\left (\frac {{\left (d^{2} e - c d f\right )} \log \left (d^{2} x^{2} + 2 \, c d x + c^{2} + 1\right )}{d^{4} e^{4} - 4 \, c d^{3} e^{3} f + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{2} f^{2} - 4 \, {\left (c^{3} + c\right )} d e f^{3} + {\left (c^{4} + 2 \, c^{2} + 1\right )} f^{4}} - \frac {2 \, {\left (d^{2} e - c d f\right )} \log \left (f x + e\right )}{d^{4} e^{4} - 4 \, c d^{3} e^{3} f + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{2} f^{2} - 4 \, {\left (c^{3} + c\right )} d e f^{3} + {\left (c^{4} + 2 \, c^{2} + 1\right )} f^{4}} - \frac {{\left (d^{4} e^{2} - 2 \, c d^{3} e f + {\left (c^{2} - 1\right )} d^{2} f^{2}\right )} \arctan \left (\frac {d^{2} x + c d}{d}\right )}{{\left (d^{4} e^{4} f - 4 \, c d^{3} e^{3} f^{2} + 2 \, {\left (3 \, c^{2} + 1\right )} d^{2} e^{2} f^{3} - 4 \, {\left (c^{3} + c\right )} d e f^{4} + {\left (c^{4} + 2 \, c^{2} + 1\right )} f^{5}\right )} d} + \frac {1}{d^{2} e^{3} - 2 \, c d e^{2} f + {\left (c^{2} + 1\right )} e f^{2} + {\left (d^{2} e^{2} f - 2 \, c d e f^{2} + {\left (c^{2} + 1\right )} f^{3}\right )} x}\right )} + \frac {\arctan \left (d x + c\right )}{f^{3} x^{2} + 2 \, e f^{2} x + e^{2} f}\right )} b - \frac {a}{2 \, {\left (f^{3} x^{2} + 2 \, e f^{2} x + e^{2} f\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 7.53, size = 399, normalized size = 1.76 \[ \frac {b\,d^3\,e\,\ln \left (e+f\,x\right )}{{\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}^2}-\frac {a\,f}{2\,{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {b\,d\,e}{2\,{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {a\,c^2\,f}{2\,{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {b\,\mathrm {atan}\left (c+d\,x\right )}{2\,f\,{\left (e+f\,x\right )}^2}-\frac {b\,c\,d^2\,f\,\ln \left (e+f\,x\right )}{{\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}^2}+\frac {a\,c\,d\,e}{{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {b\,d\,f\,x}{2\,{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {a\,d^2\,e^2}{2\,f\,{\left (e+f\,x\right )}^2\,\left (c^2\,f^2-2\,c\,d\,e\,f+d^2\,e^2+f^2\right )}-\frac {b\,d^2\,\ln \left (c+d\,x-\mathrm {i}\right )\,1{}\mathrm {i}}{4\,f\,{\left (d\,e-c\,f+f\,1{}\mathrm {i}\right )}^2}+\frac {b\,d^2\,\ln \left (c+d\,x+1{}\mathrm {i}\right )\,1{}\mathrm {i}}{4\,f\,{\left (c\,f-d\,e+f\,1{}\mathrm {i}\right )}^2} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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